Question

A velocity of a body of mass 20kg decreases from 20 m per second to 5 m per second in a distance of 100 m force on body is

Answer 1

u=20m/s
v=5m/s
s=100m
a=?

v^2=u^2+2as
5*5=20*20+2a100
25=400+200a
25-400=200a
375=200a
a=375/200
a=1.875 m/s2

Answer 2

V = 20 m/s

U = 5 m/s

S = 100 m

$v {}^{2} - u {}^{2} = 2as \\ \\ 20 {}^{2} - 5 {}^{2} = 2 \times a \times 100 \\ \\ 400 - 25 = 200a \\ \\ 200a = 375 \\ \\ a = \frac{375}{200} \\ \\ a = 1.875 \:$



Force = mass * acceleration

Force = 20 * 1.875

Force = 37.5 N