Question

a velocity of an object increases at a rate of 20 metre per second to 15 metre per second in 10 second
find its acceleration​

Answer 1

Answer:

-0.5 m/s²

Explanation:

Acceleration is defined as the rate of change of velocity,

i.e a = Δv/Δt.

It is given that Δv = 15 - 20 = -5 m/s and t = 10 s.

∴ a = -5/10

a = -0.5 m/s².

Here negative sign indicates body is slowing down or decelarating.

Answer 2

Question :

Velocity of an object increases at a rate of 20 metre per second to 15 metre per second in 10 second . Find its acceleration​ ,.

Given :

• Initial velocity of object (u) = 20 m/s
• Final velocity of object (v) = 15 m/s
• Time (t) = 10 s

To find :

• Acceleration of object

Solution :

Acceleration of an object is given by,

$\longmapsto\boxed{\boxed{\mathfrak{Acceleration, a = \dfrac{v - u}{t} }}}$

Here ,

• v = 15 m/s
• u = 20 m/s
• t = 10 s

Putting values,

$\longmapsto\sf Acceleration \ (a) = \dfrac{15 - 20}{10} \\\\ \\ \longmapsto\sf Acceleration \ (a) = \dfrac{-5}{10} \\\\ \\ \longmapsto\underline{\underline{\mathfrak{Acceleration \ (a) = -0.5 \ m/s^2 }}}$

$\therefore\underline{\textsf{Acceleration of object = {\textbf{-0.5 m/s ^2 }}}}$