A velocity-time graph for a moving object is shown
below. What would be the total displacement during
time 1 = 0 to 1 = 6 s?
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Answer:
Total displacement between t = 0 to t =6 s is the area under the graph between 0 and 6.
area=(2∗5)+ 1/2 (2∗5)− 1/2 (2∗5)=10m
Hence answer is 10m.
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