Question

A vendar bought two wooden tables for 15,500 and paid 2 350 on transportation
He sold one table at a profit of 20%
and another at
at a lo
of 4% . Find
the selling price in both the cases
and the actual profit or loss percentage
made by the vendor​

Answer 1

Step-by-step explanation:

total Cp = 15,500 + 2350

= 17850

CP SP

5 6

25 24

This question can't be further solved because

nothing is given equal { SP OR CP OF BOTH}

Answer 2

A dealer bought two tables for Rs 3120. He sold one of them at a loss of 15% and other at a gain of 36%. Then, he found that each table was sold for the same price. What is the cost price of each table?

Friends…!

Let the cost price of one table be ₹x and other table be ₹y

He sold one of them at a loss of 15% and other at a gain of 36%

One table was sold at a loss of 15%. Hence it's sale price has been 85/100 × x = 0.85x

Other table was sold at a profit of 36%. Hence it's sale price 136/100 × y = 1.36y

he found that each table was sold for the same price

Thus 0.85 x = 1.36y

x = 1.36y/0.85…Eq..1

Dealer bought two tables for Rs 3120.

It means the cost price of two tabke together was ₹3120. Accordingly

x + y = 3120…Eq..2

Substituting the value if x from Eq.1 to Eq..2

x + y = 3120

1.36y/0.85 + y = 3120

(1.36y +

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Let 1st table cost Rs.x and 2nd table Rs.y

Since first table was sold at a loss of 15% it will

be 85x/100 and the 2nd one at a profit of 36% it will be 136y/100

As per the problem 85x/100 = 136y/100

Also x + y = 3120 (given)

Solving the two equation we get:

221y = 265200

Therefore y = 1200 and hence x= 1920

Hence the CP of the two tables is Rs 1200 and Rs. 1920.

(This method useful to you solve your questions)

thankyou