Question

A vendor buys oranges 9 at ₹10 and sells them at ₹12 for ₹16. find his gain per cent
pls step by step . pls step by step​

Answer 1

Step-by-step explanation:

Cost of N no of oranges at the rate 4 for Rs 10 = (N/4)×10

Cost of N no of oranges at the rate 5 for Rs 10 = (N/5)×10

Cost of N+N = 2N orànges =10×(N/4+N/5)=9N/2 = 4.5N

Selling price of 2N oranges = 20×(2N/9) = 4.444N

Loss = (9N/2) –(40N/9)= N(81–80)/18 = (1/18)N

Cost 4.5 N , loss = (1/18)N

%of loss = {(N/18)/4.5N}× 100 = 100/81= 1.2345679%

Answer 2

Answer:

19.81%

Step-by-step explanation:

A vendor buys oranges at 9 for rs. 10

cost price of 9 oranges = 10

cost price of 1 orange = 10/9 = 1.11 rs

now,

he sells them at 12for rs.16

s.p  of 1 orange = 16/12 = 1.33 rs

now gain = sp - cp

               = 1.33 - 1.11

 

                 = 0.22

                    = 0.22 rs

now gain% = profit *100 /cp

                = 0.22*100/1.11

   

                = 22/1.11

                 = 19.81%

hope it helps u