Question

a vendor buys oranges at 9 for 10 and sells them at 12 for 16 find his gain percent​

Answer 1

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$\sf \: Cost \: Price \: of \: 9 \: oranges = Rs \: 10$

$\sf \: Cost \: Price \: of \: 1 \: orange = \dfrac{10}{9}$

$\boxed{\boxed{C.P= Rs\:1.11}}$

$\sf \: Selling \: Price \: of \: 12 \: orange = Rs 16$

$\sf \: Selling \: Price \: of \: 1 \: orange = \dfrac{16}{12}$

$\boxed{\boxed{S.P=Rs\:1.33}}$

$\sf \: Gain = S.P - C.P$

$\sf \: Gain = \: Rs \: 1.33 - 1.11$

$\boxed{\boxed{Rs\:0.22}}$

$\sf \: Gain \% = \dfrac{Gain}{C.P} \times 100$

$\sf \: Gain \% = \dfrac{0.22}{1.11} \times 100$

$\sf \: Gain \% = \dfrac{22}{1.11}$

$\boxed{\boxed{19.81\: \%}}$

Answer 2

GiVeN:-

• Cost Price(CP) of 9 Oranges is 10

• Selling Price(SP) of 12 Oranges is 16

To FiNd:-

• Gain percent

SoLuTiOn:-

Cost Price of 9 orange = 10

Then,

CP of 1 orange = 10/9

Now,

Selling Price of 12 orange = 16

Then,

SP of 1 orange = 16/12 = 4/3

Now,

We know that,

• Profit or gain = Selling Price (SP) - Cost Price (CP)

So,

Profit (P) =

$\implies \: \frac{4}{3} - \frac{10}{9} \\ \\ \implies \: \frac{4 \times 3}{3 \times 3} - \frac{10}{9} \\ \\ \implies \: \frac{12 - 10}{9} = \frac{2}{9}$

Now, Profit (P) = 2/9

We know that,

Profit % =

$\implies \: \frac{profit}{cost \: price} \times 100 \\ \\ \implies \: \frac{ \frac{2}{9} }{ \frac{10}{9} } \times 100 \\ \\ \implies \: \frac{2}{9} \times \frac{9}{10} \times 100 \\ \\ \implies \: \frac{100}{5} = 20$

Hence,

Profit or Gain percent is = 20%