Question

A vendor sells 60 percent of apples he had and throws away 15 percent of the remainder. Next day he sells 50 percent of the remainder and throws away the rest. What percent of his apples does the vendor throw?

Answer 1

let initial apple be 100
he sold 60 apples and threw 15% of 40 apples
i.e., (15÷100)×40= 6 apples
nxt day from remaining 34 apples
he sold 50% i.e., 17 apples and threw rest 17 apples...
so total no. of apples thrown is 6+17= 23 apples

% apples thrown is (23÷100)×100% = 23%.

Answer 2

Answer:

Explanation :

Let total apples be 100 first day he throws = 50*20/100 = 10 apples

next day he throws = 40*40/100 = 16 apples

so total = 26