Math, asked by Keerthana16727, 6 months ago

A vendor sold a shirt for Rs. 450 after giving the customer 10 percent discount on the display price and gain 12.5% from transaction.by what percentage vendor increase the actual price to arrive at display price​

Answers

Answered by hanshu1234
2

Step-by-step explanation:

Let the CP of the watch be Rs.x.

Case I,

Therefore, SP = 120x100=Rs.6x5120x100=Rs.6x5

Case II,

CP = Rs.(x - 100)

SP = Rs. (6x5−100)(6x5−100)

Profit = (6x5−x)=Rs.x5(6x5−x)=Rs.x5

Therefore, x5x−100×100=25x5x−100×100=25

=> 25x - 2500 = 20x

=> 5x = 2500

=> x = 2500525005 = Rs.500

Answered by dikshaagarwal4442
0

Answer:

The vendor increased the actual price by 25%.

Step-by-step explanation:

  • Step-1: Lets assume marked price = 100.

If he gives 10% discount on display price, then selling price =100 - 10 =90

But the mentioned selling price = Rs. 450

That means 90 is equivalent to 450/-.

100 is equivalent to 450 × \frac{100}{90} = 500/-. So the marked price = 500/-

  • Step-2: Profit = 12.5%. Selling price = 100+12.5 = 112.5

       That means the selling price is 112.5 when the cost price = 100

       Cost price of the shirt = 450 × \frac{100}{112.5} = 400/-

       Actual price of the shirt = cost price = 400/-

  • Step-3: Increase in actual price = marked price - actual price

                                                             = 500 - 400 = 100/-

       Increase percentage = \frac{increased value}{actual price} \times 100%

                                           = \frac{100}{400} \times 100% = 25%

     ∴ The vendor increased the actual price by 25%.

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