Question

A venturi meter is measuring the flow of water in a pipe having cross-sectional
area of 0.0038 m², a throat with cross-sectional area of 0.00031 m^2 is connected
to it. If the pressure difference is measured to be 2.4 kPa, what is the speed of
the water in the pipe?

Answer 1

Answer:

pipe having cross-sectional

area of 0.0038 m², a throat with cross-sectional area of 0.00031 m^2 is connected

to it. If

Answer 2

The continuity equation yields AV=av, and Bernoulli's equation yields 21ρV2=△p+21ρv2, where △p=p2−p1 with p2 equal to the pressure in the throat and p1 the pressure in the pipe. The first equation gives v=(A/a)V. We use this to substitute for v in the second equation and obtain 21ρV2=△p+21ρ(A/a)2V2.

The equation can be used to solve for V.

(a) The above equation gives the following expression for V:

V=ρ(1−(A/a)2)2△p=ρ(a2−A2)2a2△p

b)We substitute the values given to obtain V=ρ(a2−A2)2a2△p=(1000kg/m3)((32×10−4m2)2−(64×10−4m2)2)2(32×10−4m2)2(41×103Pa−55×103Pa)

Consequently, the flow rate is R=AV=(64×10−4m2)(3.06m/s)=2.0×−2m3/s

please mark as a brainliest