Question

A veranda of width 3m is constructed all along outside a room which is 6.5m long and 5.2m wide. find the area of the veranda. Also, find the cost of cementing the floor of the veranda at the rate of ₹220 per metre square.​

Answer 1

Answer:

Step-by-step explanation:

Given: Length of room =6.5m,  

Width of room =5.2m,  

Width of verandah which is constructed all along outside of room =3m,  

Cost of cementing of verandha = Rs 220 per sq.m

∴, width of room with verandah=5.2+3+3=11.2m

length of room with verandah=6.5+3+3=12.5m

Area of room=Length×Width=6.5×5.2=33.8m2

Area of room with verandah= Length×Width=11.2×12.5=140m2

Area of verandah=Area of room with verandah−Area of room=140−33.8=106.2m2

Cost of cementing of verandah=Area×Rate=106.2×Rs.220=Rs.23364

2

Answer 2

$\sf\red{GIVEN}$

$\sf{Length \: of \: room = 6\: m}$

$\sf{Width \: of \: room = 5\: m}$

$\sf{Width \: of \: verandah\:which \:is \:constructed \: all\: along\:outside\: of \: room = 3\: m}$

$\sf{Cost\: of\: cementing\: of\:verandah = ₹ 2.05{m}^{2}}$

$\sf\red{\therefore Length \: of \: room \: with \: verandah = 6m+3m+3m = 12m}$

$\sf\red{Width\:of \:room \: with\: verandah=5m+3m+3m=11m}$

$\sf\red{Area \:of \:room = Length × Width }$

$\implies$$\sf{6m×5m}$

$\implies$$\sf{30 {m}^{2} }$

$\sf\red{Area \: of \: room \: with \: verandah = Length × Width}$

$\implies$$\sf{12m×11m}$

$\implies$$\sf{132{m}^{2}}$

$\sf\red{Area\:of \: verandah=\: Area\: of\:room \: with\:verandah-Area \: of \: room}$

$\implies$$\sf{132 {m}^{2} - 30 {m}^{2}}$

$\implies$$\sf{ {102m}^{2} }$

$\sf\red{Cost \:of \: cementing\: of\: verandah=\: Area × Rate}$

$\implies$$\sf{ {102m}^{2} \times {₹2.05m}^{2} }$

$\implies$$\sf{₹209.1}$