Question

A verandah 1 m wide is constructed all along the
outside of a room 5 m long and 4 m wide. Find
(i) the area of the verandah
(11) the cost of cementing the floor of the
verandah at the rate of 25 per m²






with solution​

Answer 1

Answer:

(i) Area of the verandah = 22 $m^2$

(ii) the cost of cementing the floor of the verandah at the rate of 25 per $m^2$ = ₹550

Step-by-step explanation:

The room is 5 m long and 4 m wide.

Area of the room = 5 x 4 $m^2$ = 20 $m^2$

The verandah is 1 m wide and was constructed all along the outside of the room.

Length of the verandah = Length of the room + Twice the width of the verandah = 5 m + 2x1 m = 7 m

And the width of the verandah = Width of the room + Twice the width of the verandah = 4 m + 2x1 m = 6 m

Therefore, Area of the room, including the verandah = 7 x 6 $m^2$ = 42 $m^2$

(i) Area of the verandah = Area of the room including verandah - Area of the room

= 42 $m^2$ - 20 $m^2$ = 22 $m^2$

(ii) the cost of cementing the floor of the verandah at the rate of 25 per $m^2$ = ₹22 x 25 = ₹550

Answer 2

Answer:

(i) Area of the verandah = 22 $m^2$

(ii) the cost of cementing the floor of the verandah at the rate of 25 per $m^2$ = ₹550

Step-by-step explanation:

The room is 5 m long and 4 m wide.

Area of the room = 5 x 4 $m^2$ = 20 $m^2$

The verandah is 1 m wide and was constructed all along the outside of the room.

Length of the verandah = Length of the room + Twice the width of the verandah = 5 m + 2x1 m = 7 m

And the width of the verandah = Width of the room + Twice the width of the verandah = 4 m + 2x1 m = 6 m

Therefore, Area of the room, including the verandah = 7 x 6 $m^2$ = 42 $m^2$

(i) Area of the verandah = Area of the room including verandah - Area of the room

= 42 $m^2$ - 20 $m^2$ = 22 $m^2$

(ii) the cost of cementing the floor of the verandah at the rate of 25 per $m^2$ = ₹22 x 25 = ₹550