Math, asked by aditilodhi2008, 1 month ago

A verandah of width 2.25 m is constructed all

along outside a room which

is 5.5 m long and 4 m wide. Find:

(i) the area of the verandah.

(ii) the cost of cementing the floor of the
verandah at the rate of ₹ 200 per m2.​

Answers

Answered by SAMYAKMAHINDRAKAR
10

Answer:

Given: Length of room =5.5m,

Width of room =4m,

Width of verandah which is constructed all along outside of room =2.25m,

Cost of cementing of verandha = Rs 200 per sq.m

∴, Length of room with verandah=5.5+2.25+2.25=10m

Width of room with verandah=4+2.25+2.25=8.5m

Area of room=Length×Width=5.5×4=22m

2

Area of room with verandah= Length×Width=10×8.5=85m

2

Area of verandah=Area of room with verandah−Area of room=85−22=63m

2

Cost of cementing of verandah=Area×Rate=63×Rs.200=Rs.12600

Attachments:
Answered by TYKE
4

Given: Length of room =5.5m,

Width of room =4m,

Width of verandah which is constructed all along outside of room =2.25m,

Cost of cementing of verandha = Rs 200 per sq.m

∴, Length of room with verandah=5.5+2.25+2.25=10m

Width of room with verandah=4+2.25+2.25=8.5m

Area of room=Length×Width=5.5×4=22m

2

Area of room with verandah= Length×Width=10×8.5=85m

2

Area of verandah=Area of room with verandah−Area of room=85−22=63m

2

Cost of cementing of verandah=Area×Rate=63×Rs.200=Rs.12600

Similar questions