Math, asked by aqsakhan456, 1 year ago

a verandah of width 2.25 m is constructed all alongs outside a room which is 5.5 m long and 4m wide find..

(1) the area of the verandah
(2) the cost of cementing the floor of the verandah at the rate of rupes200 per m square......

Answers

Answered by Anonymous001
15
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i) It is given in the question that,
Length of room = 5.5 m

Breadth of room = 4 m
We know that,

Area of rectangle = Length × Breadth
∴ Area of room = 5.5 × 4
= 22 m2

From the figure it can be observed that the new length and breadth of the given room (When verandah is included) is 10 m and 8.5 m respectively

∴ Area of room including verandah = 10 × 8.5
= 85 m2

Area of verandah = Area of the room including verandah – Area of room
= 85 – 22
= 63 m2


(ii) It is also given in the question that,
Cost of cementing 1 m2 area of the floor of the verandah = Rs 200

∴ Cost of cementing 63 m2 area of the floor of the verandah = 200 × 63

= Rs 12600

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Answered by samitsikdar1974
4

This is the answer to your question.

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