A Verify the property ax(bxc) (axb)xc by taking a= 3/4. b= -1/2. c= -7/5
Answers
Answered by
13
a×(b×c)=(a×b)×c
a=3/4
b=-1/2
c=-7/5
=>3/4×(-1/2×7/5)=(3/4×-1/2)×7/5
=>3/4×-7/10=-3/8×7/5
=>-21/40=-21/40
LHS=RHS
Proved
a=3/4
b=-1/2
c=-7/5
=>3/4×(-1/2×7/5)=(3/4×-1/2)×7/5
=>3/4×-7/10=-3/8×7/5
=>-21/40=-21/40
LHS=RHS
Proved
Answered by
22
Hi ,
It is given that ,
a = 3/4 , b = -1/2 , c = -7/5
LHS = a × ( b × c )
= 3/4 × [ ( -1/2 ) × ( - 7/5 ) ]
= 3/4 × ( 7/10 )
= ( 3 × 7 )/ ( 4 × 10 )
= 21/40 ----( 1 )
RHS = ( a × b ) × c
= [ 3/4 × ( - 1/2 ) ] × ( - 7/5 )
= [ - 3/8 ] × ( - 7/5 )
= ( 3 × 7 ) / ( 8 × 5 )
= 21/40 -----( 2 )
From ( 1 ) and ( 2 ) ,
LHS = RHS
a × ( b × c ) = ( a × b ) × c
[ Associative proporty under
multiplication ]
I hope this helps you.
: )
It is given that ,
a = 3/4 , b = -1/2 , c = -7/5
LHS = a × ( b × c )
= 3/4 × [ ( -1/2 ) × ( - 7/5 ) ]
= 3/4 × ( 7/10 )
= ( 3 × 7 )/ ( 4 × 10 )
= 21/40 ----( 1 )
RHS = ( a × b ) × c
= [ 3/4 × ( - 1/2 ) ] × ( - 7/5 )
= [ - 3/8 ] × ( - 7/5 )
= ( 3 × 7 ) / ( 8 × 5 )
= 21/40 -----( 2 )
From ( 1 ) and ( 2 ) ,
LHS = RHS
a × ( b × c ) = ( a × b ) × c
[ Associative proporty under
multiplication ]
I hope this helps you.
: )
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