Question

A vernier calipers of least count 0.01 cm has checked for zero error, the zero mark on the vernier scale has found towards right and it's 3rd mark was in the line with some mark on the main scale . When the instrument was used to determine the diameter of a given bob, the main scale reading was 2.1 cm and 6th division was found to be coinciding with some division on main scale. Calculate it's zero error and corrected diameter of the given bob​

Answer 1

Answer:

Explanation:

Least count, LC=0.01cm

Here the negative zero error of callipers =5×0.01=0.05cm and it should be added to final reading.  

Main scale reading, MSR=2.4cm and VSD=6

So total reading means the diameter of sphere R=MSR+(VSD×LC)+ zero error =2.4+(6×0.01)+0.05=2.51 cm