A vernier calliper has 20 division on the vernier scale which coincide with 19divisions on the main scale.yhe the least count of instrument is 0.1mm the msd are of 1)0.5mm 2)1mm 3)2mm 4)1/4mm
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1
Explanation:
least count =
(minimum no. of div on main scale)/
total no. of div on vernier scale
0.1 = (msd)/20
msd = 2 mm
option 3 is correct
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