A vernier has 10 divisions and they are equal to
9 divisions of main scale in length. If the main scale
is calibrated in mm, what is its least count?
Answers
Answered by
2
Answer:
Explanation:
Least count can calculated using the formula.
Least Count=Length of1 MSD–Length of I VSD
Where MSD and VSD refer to Main Scale Division and Vernier Scale Division respectively. Here 10 divisions on main scale coincide with 9 divisions on vernier scale.
So, 1 VSD is equivalent to 0.9 main scale divisions.
Using the formula for Least Count, we get LC=1MSD–1VSD=1MSD–0.9MSD=0.1MSD=0.1×1mm=0.1mm
As Given, 1MSD=1mm
Similar questions