Physics, asked by ykumkum6718, 11 months ago

A vernier has 10 divisions and they are eual to 9 divisions of main scale in length. If the main scale is calibrated in mm, what is its least count?

Answers

Answered by dhairyaharshji
0

Answer:

Explanation:

Least count= 1MSD - 1 VSD

BUT:: 1VSD = 9/10MSD

SO LEAST COUNT = 1MSD - 9/10MSD (1VSD)

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