A vernier scale with 10 divisions slides over a main scale whose pitch is 0.5 mm (pitch =1 MSD) . If a bob of diameter 9.75 mm is held between the jaws determine the M.S.R and V.S.R if
(a) there is no zero error,
(b) the zero error = 0.35 mm .
Answers
Answered by
2
Answer:
Explanation:
Pitch =5mm10= 0.5 mm , least count
=0.5N=12N
Diameter =PSR +C.S.C.D. × L.C.
=xp+y.PN=P(x+.yN)
x+.yN=5.48
Since .yN< pitch x+.yN=5+0.48 ltbgt x=5
yN=0.48⇒y=0.48N
Thus the CSCD depends on the number the of divisions on the circular scale for example if the number of circular scale divisions is 100 the CSCD is 48 P.S.R =5
L.C.=12N
C.S.C.D=0.48N
pls mark me as brainlist
Similar questions