Question

A vertex of a square is at the origin and its one side lies along the line 3x - 4y - 10 = 0. Find the area of the square.

Answer 1

Answer:

The area of square is 4 square units.

Step-by-step explanation:

A vertex of a square is at origin and its on side lies along the line 3x - 4y - 10 = 0

One vertex origin (0,0) and a side opposite to vertex along line 3x - 4y - 10 = 0

Perpendicular distance from origin to line would be side of square.

Using distance formula of point and line,

$D=\dfrac{ax_1+by_1+c}{\sqrt{a^2+b^2}}$

where, $(x_1,y_1)\rightarrow (0,0)$

$D=\left | \dfrac{0\cdot 3-0\cdot 4 - 10}{\sqrt{3^2+4^2}} \right |$

$D=\dfrac{10}{5}\Rightarrow 2$

Side of the square = 2 unit.

Area of square = side x side

Area of square = 2 x 2 = 4 square unit.

Thus, The area of square is 4 square units.

Answer 2

Step-by-step explanation:

the above answer is correct

may this verification helps