a vertex of an equilateral triangle is 2, 3 and the equation of the opposite side is X + Y = 2 find the equation of the other side of the triangle
class 11 straight lines
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Step-by-step explanation:
Given vertex of an equilateral triangle is A(2, 3)
Given equation of one side of triangle is x + y = 2 Clearly , point A does not lie on it, hence given equation of line BC.
Slope of line BC = -1
SInce it is equilateral the angle between the sides will be 60°.
Let the slope of the other side be m
=> | m - (-1)|/ 1 +(-1)m = tan 60° = √3
=> |m + 1|/(1-m) = √3
=> m + 1 = ±√3(1 - m)
=> m(√3 + 1) = √3 - 1 or m(√3 -1) = 1 + √3
=> m = (√3 - 1)/(√3 + 1) or (√3 + 1)/(√3 - 1).
Hence the equation of other sides of triangle are
y - 3 = (√3 - 1)/(√3 + 1) (x - 2) and
y - 3 = (√3 + 1)/(√3 - 1) (x - 2)
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