A vertial pole of height 5.60m casts a shadow of length 3.20m on the horizontal earth surface. Under the similar conditions and at the same time, find: (1) the length of the shadow casted by another vertical pole of height 10.5 m.
(2) the vertical height of the pole which casts a shadow of length 5 m.
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5.6/3.2=10.5/x cross multiply.
5.6x=3.2*10.5
5.6x=33.6
x=33.6/5.6
x=6 meters.
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5.6/3.2=x/5
3.2x=5.6*5
3.2x=28
x=28/3.2
x=8.75 mwters.
5.6x=3.2*10.5
5.6x=33.6
x=33.6/5.6
x=6 meters.
----------------
5.6/3.2=x/5
3.2x=5.6*5
3.2x=28
x=28/3.2
x=8.75 mwters.
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