Question

A vertical bar magnet is
dropped from position on the
axis of a fixed metallic coil as
shown in fig - I. In fig - II the
magnet is fixed and horizontal
coil is dropped. The accelera-
tion of the magnet and coil are
a1 and a2 respectively then
S
IN
d
fixed
fixed UN
fig-11
fig - 1​

Answer 1

Answer:

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Explanation:

When a bar magnet is dropped across a current carrying coil, emf is induced in the coil. emf appears as pulses when the bar magnet enters the loop and exits the loop. Induced emf is equal in magnitude to rate of change of magnetic flux but sign of emf is opposite to sign of flux change

if flux increases emf is negative and if the flux decreases then emf is positive. when the bar magnet enters there is a change in magnetic flux across the coil and flux increases hence induced emf is negative. Similarly when the bar magnet its, induce emf is positive. when the bar magnet is fully inside there will not be any flux change and no induced emf in the coil

When the bar magnet enters emf induced in the coil and creates induced current and induced magnetic field. This induced magnetic field opposes the magnetic filed of bar magnet and reduces the falling speed of bar magnet. Due to this bar magnet entrance will present more time with coil and we get longer pulse. When bar magnet leaves this slowing effect is reduced and speed of falling magnet will be more. Hence at the time of exit the pulse length of induced emf is shorter.