Question

a vertical circular coil of one turn and radius 9.42cm is placed with its plane in magnetic needle is pivoted at the centre of coil so that it can freely rotate in the horizontal plane.If a current of 6A is passed through the coil, then the needle deflects by(BH=4×10 power -5 Tesla)????​

Answer 1

Hey Dear,

◆ Answer -

Deflection of needle = 45°

● Explaination -

# Given -

r = 9.42 cm = 9.42×10^-2 m

n = 1 turn

I = 6 A

B = 4×10^-5 T

# Solution -

Deflection of the coil is calculated by formula -

tanθ = μ.n.I / 2.r.B

tanθ = (4π×10^-7 × 1 × 6) / (2 × 9.42×10^-2 × 4×10^-5)

tanθ = 1

Taking tan inverse -

θ = arctan(1)

θ = 45°

Therefore, the needle deflects through 45°.

Best luck for exams, buddy.