Question

A vertical cylindrical tank with a diameter of 12m and a depth of 4m is filled witb water to the top at 20°C. If the water is heated to 50°C, how much water will spill over? Unit weight of water at 20°C is 9.79kn/m^3 and 9.69kn/m^3, respectively

Answer 1

Step-by-step explanation:

Attachment contains the stepwise explanation and solution of the problem.

Answer 2

Answer:

water spilled by rise in temperature is 4.67m³

Step-by-step explanation:

Given :  Diameter =12m , Height = 4m

unit weight or specific weight at 20° C ($d_{20}$)= 9.79 kN/m³

unit weight or specific weight at 50° C( $d_{50}$ ) = 9.69 kN/m³

Volume at 20° C = πd²h/4 = 3.14x(12)²x4/4

                                     = 452.16m³

 $d_{50}$ = M/$V_{50}$  ,  $d_{20}$=M/$V_{20}$

Then,    $d_{20}$/ $d_{50}$  = M/$V_{50}$ / M/$V_{20}$

             $d_{20}$/ $d_{50}$  = $V_{50}$/ $V_{20}$

             ∵ $V_{50}$/ $V_{20}$  = 9.79 / 9.69

now , water spilled by rise in temperature = volume at 50° C - volume at 20° C

⇒  $V_{50}$ -$V_{20}$

⇒ $V_{20}$   (  $V_{50}$/ $V_{20}$  - 1 )

⇒ 452.16 ( 9.79 / 9.69 - 1 )

⇒ 452.16(0.1/9.69)

⇒ 452.16/96.9

⇒4.67m³