Question

A vertical double acting steam engine develops 75 kw at 250 rpm. The maximum and minimum speeds are not to vary more than 1% on either side of mean speed. Find the mass of flywheel if radius of gyration is 0.6 m. If coefficient of fluctuation of energy 30% per stroke.

Answer 1

The mass of the flywheel is 547 kg.

Explanation:

Given data:

• Power=75 kW
• N = 250 rpm
• ω1 - ω2 = 1%
• ω = 0.01ω
• k = 0.6
• Cs = ω1 - ω2/ ω = 0.01

Maximum fluctuation of energy "Δ E" = Work done per cycle × CE

WD/cycle = P x n/60

Where n = no of working strokes/min

P = Power developed in watts

WD/ cycle = (75 x 10^3 ) x 60/250 = 18,000 N-m^2

We know that Δ E = mk^2 ω^2Cs

Mass of the flywheel= 547 kg

Thus the mass of the flywheel is 547 kg.

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