A vertical electric wire in the wall of a building carries a dc current of 20 a upward. What is the magnitude of the magnet field at a point 0.1 m due north of this wire? Answer in units of μt.
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B = μI / 2(π)r
= (4π×10^−7 Tm/A)(20A) / 2π(0.1m)
= (2x10^-7 Tm/A)(20A) / (0.1m)
= 4x10^-5T
= 40 µT
I hope this helps you
= (4π×10^−7 Tm/A)(20A) / 2π(0.1m)
= (2x10^-7 Tm/A)(20A) / (0.1m)
= 4x10^-5T
= 40 µT
I hope this helps you
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