a vertical lenght of 6m cast A SHADOW 400cm long on the ground and at the same time a tower casts a shadow 28m long ,using similarity,find the height of the tower
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Step-by-step explanation:
Heya !!
Given :-
- Length of the vertical pole = 6m
- Shadow of the pole = 4 m
- Length of shadow of the tower = 28
To Find :-
- find the height of the tower
Supposed Height of tower = h m
In ΔABC and ΔDEF,
∠C = ∠E (angular elevation of sum)
∠B = ∠F = 90°
∴ ΔABC ~ ΔDEF (By AA similarity criterion)
∴ AB/DF = BC/EF
putting value
⇒ 6/h = 4/28
⇒ 4h = 6×28
⇒ 4h = 168
⇒ h = 168/4
⇒ h = 42
Hence, the height of the tower is 42 m.
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