Question

A vertical narrow glass tube of unform cross-section closed at one end has air filled in it
Upto 40 cm of height with a column of Mercury
of height 10cm above it if the tube is gradually inclined in a vertical plane and brought to a position making an angle of 60 degree's with the vertical then the new length of air column entrapped with in the tube is (atmospheric pressure =76cm of hg)
a) 45.47 cm
b) 43. 47 cm
C) 42.47cm
d) 44.47 cm​

Answer 1

Given:

A vertical narrow glass tube of uniform cross-section

The height =40cm of height

Column of mercury of height =10cm

Angle=60°

To Find:

Length of air column entrapped with in the tube

Solution:

P=hρg

P×40×A=ρ₁×(50)×A

⇒ρ₁=45/45+1×(45−x)×ρ₂

​h₁=44.47cm

Answer:

D) 44.47 cm​

Answer 2

ANSWER

44.47 is the answer