Question

A vertical pole 10m long casts a shadow of 5m long on the ground at the same time a tower casts a shadow 12.5 m long on the ground,the height of tower is?​

Answer 1

Answer:

625m????

Step-by-step explanation:

hindi ako sure check mo nlng

Answer 2

The height of the tower is 25 m.

Given:

• A vertical pole 10m long, casts a shadow of 5m long on the ground.
• At the same time a tower casts a shadow 12.5 m long on the ground.

To find:

• Find the height of the tower.

Solution:

Concept/Formula to be used:

• Draw the situation by a right angle triangle.
• Use application of trigonometry, at the same time the sun's elevation angle is the same.

Step 1:

Find the Sun's elevation angle.

Draw the situation.

*See the attachment.

In right triangle ∆ABC.

$tan\:C=\frac{AB}{BC}$

$tan\:C=\frac{10}{5}$

$\bf tan\:C=2$

Step 2:

Find the height of the tower.

At the same time another tower DE, casts a shadow EF= 12.5 m.

tan C= tan F (Sun's Angle of elevation is same)

$tan\:E=\frac{DE}{EF}$

$2 = \frac{DE}{12.5}$

$DE= 2 \times 12.5$

$\bf DE = 25 \: m$

Thus,

The height of the tower is 25 m.

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