A vertical pole 20 m long cast a shadow 20√3 m long. Find the sun’s
altitude. At the same time, a tower casts a shadow 90 m long ,
determine the height of the tower
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In ΔABC & ΔADE
∠BCA=∠DEA=90o [Each are at 90o to the ground]
∠BAC=∠DAE [common angle]
∠CBA=∠EDA [∵ the sum will cast light a equal angles]
Hence, by AAA, ΔABC∼ΔADE
⇒CABC=EADE
⇒1020=50DE
⇒DE=100
∴ The height of the tower is 100m.
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