A vertical pole 40m long casts a shadow 20m long on the ground At the same time tower shadow 50m long cm the ground Find height of second tower.
Answers
Explanation:
Given : A vertical pole 40m long cast shadow 20m long on the ground.
On the same time , A tower casts a shadow 50m.
Both pole and tower are standing straight to the ground and the rays of the sun will fall at same angle for both the structures.
So both triangles made with the shadow would be similar.
⇒ The corresponding sides should be proportional.
⇒\dfrac{\text{Height of pole}}{\text{Length of pole's shadow}}=\dfrac{\text{Height of tower}}{\text{Length of tower's shadow}}
Length of pole’s shadow
Height of pole
=
Length of tower’s shadow
Height of tower
Substitute values.
⇒\dfrac{40}{20}=\dfrac{\text{Height of tower}}{50}
20
40
=
50
Height of tower
⇒2=\dfrac{\text{Height of tower}}{50}2=
50
Height of tower
⇒\text{Height of tower}=2\times50=100Height of tower=2×50=100
Hence, the height of the tower is 100 meters.