Question

A vertical pole 5m 60cm high casts a shadow 3m 20cm long. Find at the same time i) The length
of the shadow cast by another pole 10m 50 cm high i) the height of a pole which casts a
shadow of 5m long.​

Answer 1

Step-by-step explanation:

ANSWER

Let x m be the length of the pole whose shadow is of length 10m50cm.

Let y m be the length of the pole whose shadow is 5m long.

Clearly, it is a case of direct variation.

i)

3.20

5.60

=

x

10.50

x=

5.60

10.50×3.20

=6

Hence, the length of the shadow is 6m.

ii)

3.20

5.60

=

5

y

x=

3.20

5.60×5

=8.75

Hence, the length of the pole is 8.75 meters.