Question

A vertical pole 5m long casts a shadow 2m long on the ground at the same time a tower caste a shadow 25m long on the ground. Find the height of the tower

Answer 1

let Ab be the vertical pole of 5m which cast a shadow of 2m on ground now Pq is another tower which cast a shadow of 25 m

therefore we have two triangle Abc And Pqr

in Δabc &Δpqr

angle abc= angle pqr(each 90)

angle bca=angleqrp(angle of elevation)

hence, Δabc~Δpqr(aa similarly)

ab/pq=bc/qr (sides propertionate)

$5 \div pq = 2 \div 25$

pq= 25*5/2=62.5

pq 62.5 m

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