Question

A vertical pole AB is standing at the centre B of square PQRS. If PR subtends an angle of 90° at the top, A of the pole than the angle subtended by the side of the square A is...?

Answer 1

Answer:

The question is solely based how u imagine 3d figure in 2d figure .. try putting your pen vertically in center of the square .. then u will notice that because it lies on center of square that will be the middle point of the diagonal then u will notice that pa = ar (observe while keeping the pen).

Angle apb = arb =45 (because angle a is 90) .

Then take triangle abr

Tan r or tan 45 = height of pole (ab) / half of diagonal (br)

Ab = br = a/root2

Now again triangle abr

Angle b is 90 because pole is standing vertically . Hence apply pythagoras property

Ar square = ab square + br square

Ar = 2 will come

Ar=pa = 2

Now again put your pen at center of square. We have seen that ar=2. Now if one vertex that is a is making a distance of 2 unit till the top of the pole which is at center then all the sides must also make the same distance to the top of the pole.

I am taking side pq here

Pa = pq = qa =2

Hence paq is equilateral triangle

Angle paq =60 ( angle made by side pq )

Answer 2

Answer:

Answer 60 degree

Imagine as 3D image

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