Question

a vertical pole of 10m casts a shadow of 8mat a certain time of the day.the length of the shadow cast by a tower standing next to the pole of height 110m ​

Answer 1

Answer:

The angle subtended by the sun with the horizontal is given by

tanФ = 10÷8 = 5÷4

Now the height of the pole is 110m which is the opposite side.

tanФ = 110 ÷ length of the shadow

5÷4 = 110 ÷ length of the shadow

length of the shadow = 5× 110÷ 4

                                     =137.5 m