Question

A vertical pole of length 6 m casts a shadow 4 m long on the ground and at the same time a tower casts a shadow 28 m long. Find the height of the tower. ​

Answer 1

Answer:

42m

Step-by-step explanation:

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Answer 2

$\huge\underline\mathrm{SOLUTION:-}$

Given:

• Length of the vertical pole = 6 m
• Shadow of the pole = 4 m

Let the height of the tower be h m.

• Length of the shadow of the tower = 28 m

$\bf \underline \red {Figure\:Provided\:in\:the\:above \:attachment.}$

In ΔABC and ΔDFE,

∠C = ∠E (angle of elevation)

∠B = ∠F = 90°

By AA similarity criterion:

ΔABC ~ ΔDFE

• We know that the corresponding sides of two similar triangles are proportional.

AB/DF = BC/EF

➠ 6/h = 4/28

➠ h = (6 ×28)/4

➠ h = 6 × 7

➠ h = 42

• Hence, the height of the tower = 42 m.

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