Question

A vertical pole of length 6 m casts a shadow
4 m long on the ground and at the same
time a tower casts a shadow 28 m long.
Find the height of the tower.​

Answer 1

Answer:

42

Step-by-step explanation:

As these two triangles are congruent by RHS criterion

Thus their sides are in ratio

So AB/PQ= BC/QR

6/x= 4/28

168=4x

x= 42

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Answer 2

Solution:

Given,

• Length of the vertical pole = 6 m
• Shadow of the pole = 4 m

Let the height of the tower be h m.

Length of the shadow of the tower = 28 m

In ΔABC and ΔDFE,

∠C = ∠E (angle of elevation)

∠B = ∠F = 90°

By AA similarity criterion,

ΔABC ~ ΔDFE

We know that the corresponding sides of two similar triangles are proportional.

AB/DF = BC/EF

6/h = 4/28

h = (6 ×28)/4

h = 6 × 7

h = 42

Hence,

The height of the tower is 42 m.