A vertical pole of length 6cm casts a shadow 4m long on the ground .At the same time another tower casts a shadow 30m long .find the height of the tower
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Now we have been given a vertical pole of 6m which casts a shadow of 4m on the ground and at the same time, a tower casts a shadow 28m long. We have let the angle of inclination be θ in ΔABC. We know that tanθ=pB . Therefore, the height of tower DE=42
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