Math, asked by anwe71, 1 year ago

A vertical pole of length 6m casts a shadow 4m long on the ground and at the same time a tower casts a shadow 28m long.find the height of the tower

Answers

Answered by basappasharanu7

164 meter

6meter=4meter shadow

Xmeter=28meter shadow

After substitution,

X+4/6=28

X+4=28*6

X+4=168

X=168-4

X=164

anwe71: answer is wrong

lokesh151: maybe 26m

anwe71: Ans is 42m

Answered by lakshay24032004

The shadow is 4m and height of pole is 6m so

Base = 4m

Perpendicular = 6m

Tan = P/B = 3/2

Let height of tower be x

3/2 = x/28

x =28 × 3 ÷ 2

x =42 m

anwe71: Answer is right but it's a question of triangles not trigonometry

anwe71: and we have to use similarity for this

lakshay24032004: I have just mentioned Tan but if you notice the step that is like

lakshay24032004: 3/2 = x/28

lakshay24032004: This is similarity only

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