a vertical pole of length 6m casts a shadow 4m long on the ground and at the same time a tower casts a shadow 28m long.Find the height of the tower.
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height of pole =AB=6m
length of shadow of pole =BC=4m
length of shadow of power=ef=28m
so in ∆ abc and ∆ def ,
angle b=angle c=90°
angle c=angle f
so,by aa similarity
∆abc~∆def
so,
ab/de=BC/ef
6/de=4/28
6×28/4=de
6×7=de
de=42m
therefore,the height of the tower is 42m
length of shadow of pole =BC=4m
length of shadow of power=ef=28m
so in ∆ abc and ∆ def ,
angle b=angle c=90°
angle c=angle f
so,by aa similarity
∆abc~∆def
so,
ab/de=BC/ef
6/de=4/28
6×28/4=de
6×7=de
de=42m
therefore,the height of the tower is 42m
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ab/de=bc/ef
6×28/4=de
6×7=de
de=42
6×28/4=de
6×7=de
de=42
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