Question

A vertical pole of length Gm casts a
Shadow 4m long on the ground and
at the same time a tower casts a
Shadow 28m long find the height of
the touer​

Answer 1

Correct Question :

A vertical pole of length 6 m casts a shadow 4 m long on the ground and at the same time a tower casts a shadow 28 m long. Find the height of the tower.

Solution :

Let height of tower be "M" m.

Now,

We have given a pole whose height is 6 m and it's shadow is 4 m long.

$\implies\:height\::\:shadow$

$\Rightarrow\:6\::\:4$ ____ (eq 1)

Similarly,

A tower of height "M" m casts a shadow of 28 m.

$\implies\:height\::\:shadow$

$\Rightarrow\:M\::\:28$ ____ (eq 2)

From above we have,

$\Rightarrow\:height\::\:shadow$

$\Rightarrow\:6\::\:4$

$\Rightarrow\:M\::\:28$

Cross multiply them

$\implies\:6\:\times\:28\:=\:M\:\times\:4$

$\implies\:168\:=\:4M$

$\implies\:M\:=\:42$

∴ Height of the tower is 42 m.

Answer 2

ANSWER :

Diagram :Refer the attached picture.

Explanation :

Let the height of the tower be h m.

Here, Triangle ABC and EFG are similar.

ABC ~ EFG

So, $\mathsf{\dfrac{AB} {EF} = \dfrac{ BC} {FG}}$

$\mathsf{\dfrac{6} {h} = \dfrac{ 4} {28}}$

$\mathsf{\dfrac{6} {h} = \dfrac{ 1} {7}}$

h = 6 × 7

h = 42 m.

Hence, Height of the tower is 42 m.