a vertical pole stands on the level ground from a point on the ground 25 m away from the foot of the pole, the angle of elevation of it's top is found to be 60 degree find the hieght of the pole.
(take √3 =1.73)
Please someone solve this quickly
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•Let AB be the pole standing on a level ground and Let O be the position of the observer .Then ,OA=25 cm,
∠OAB=90⁰ and ∠AOB=60⁰
Let AB=h meters
From right △OAB ,we have
AB/OA=tan60⁰=√3
=h/25=√3
=h=(25×1.732)=43.3
Hence,the height of the pole is 43.3 m
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