Question

A vertical rectangular plane surface is submerged in water such that its top and bottom surfaces are 1.5 m and 6.0 m res-pectively below the free surface. the position of centre of pressure below the free surface will be at a distance of a)3.75 m b)4.0 m c)4.2m d)4.5m

Answer 1

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4.2

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Answer 2

Answer:

Option A is correct.

Step-by-step explanation:

Distance between free surface and top surface of plane = 1.5 m

Distance between free surface and bottom surface of plane = 6 m

⇒ Length of the Plane Surface = 6 - 1.5 = 4.5 m

Center of pressure is at the middle of the plane surface.

Middle point of the plane surface = 4.5 / 2 = 2.25 m

So, Distance of position of center of pressure below the free surface = 2.25 + 1.5 = 3.75 m

Therefore, Option A is correct.