Question

a vertical rod of length l is moved with constant velocity V towards East. The vertical component of earth's magnetic field is B and angle of dip is theta. The induced emf in the rod is ​

Answer 1

Answer:

                  Induced  E.M.F =Blv cotθ

Explanation:

Given:

Length of the rod= L

Velocity of the rod = v

Magnetic flux= B  cosθ

Vertical Component of Magnetic Flux= B' sinθ

According to Faraday's Law :

      Induced E.M.F = Magnetic flux density x Width x Speed

E.M.F= B×l×v cosθ

   

where , $Magnetic \ flux (B)=B'sin0 \\B'=\frac{B}{sin0}=B_{H} \\B_{H}=B'cos0\\Hence. \ B=\frac{Bcos0}{sin0},as \ cot0=\frac{cos0}{sin0}\\ so B=B \ cot0$

$E.M.F (e)= B cot0 *l*v \ \\E.M. F (e)=Blv \ cot0$

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Answer 2

Answer:

here dip angle is theta

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