Question

A vertical spiral spring of unstretched length 11cm has a stone attached to its lower end. When a 100g mass is added, the new length is 17cm, when a300g is added again, its length is 26cm.Calculate the mass of the stone
answer me fast

Answer 1

Answer:

Mass of stone is 100 grams.

Explanation:

The extension in a string is directly proportional to force applied on it.

So, F = k · x

Now, let mass of the stone be m. So, it applies force mg.

A/c to the situations given, following equations can be written-

mg + 100g = k · (17 - 11)

⇒(m+100)g = 6k

And,

mg + 400g = k · (26-11)

⇒(m+400)g = 15k

Diving first equation by second,

$\frac{m+100}{m+400}=\frac{6}{15}$

m = 100 g

Answer 2

Answer:

Use Hooke's law

33¹/₃ g which equals 0.3269N.

Explanation:

Hookes law calculates almost everything to do with a spring.

the previous answer seems wrong

1 Gram = 0.0098N

therefore, 300g-100g=200g

200g= 0.9807 x 2 = 1.9614N

so, for every 1.9614N attached, the spring extends 26-17=9cm.

as such we can now apply this rate of change to the original length difference

100g should give us 4.5cm displacement as it is half of 200g, so

17-4.5= 12.5cm with only the stone

so 12.5-11=1.5 cm displacement by the stone.

so using the rate we found earlier, 200g gives us 9cm, so 1.5cm gives us 33¹/₃ g, which equals 0.3269N.