Question

A Vertical Spring Is Stretched By 3 Cm When A Load Of 3 Kg Is Attached To It. What Will Be The Period Of Oscillation Of Spring When A Load Of 2.45 Kg Is Attached To It? (a) 0.415 S (b) 0.315 S (c) 0.215 S (d) 0.115 S

Answer 1

the time period of the oscillation is option B) 0.315 s

Explanation:

By hook's law

L∝ F

=>L₂/L₁ = F₂/F₁

=> l/3 = 2.45/3

=> l = 2.45 cm = 0.0245m

We know that the Time period is given by,

T = 2π√(l/g)

=> T = 2 x 3.14 x √(0.0245/9.8)

= 2 x 3.14 x 0.05

= 0.314s ≅ 0.315 s

Hence the time period of the oscillation is option B) 0.315 s

Answer 2

Answer:this questions belong to which class chapter

Explanation: