A vertical stick 1 m long cast a shadow 50 cm long. At the same time a tower casts a shadow 30m long. Determine the height of the tower.
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Answered by
6
Answer:
Step-by-step explanation:
Let AB be the stick and BC be the shadow
Let DE be the tower abd EF be the shadow
Angle of elevation(theta) in both case will be same since the sun's alt in both cases are same
tan(theta) in case 1 is equal to tan(theta) in case 2
so,
AB/BC = DE/EF
100/50 = DE/30
2 = DE/30
DE = 60cm
So, the height of tower is 60cm
Hope for brainliest!!!
Answered by
1
Answer will come in m.
That is 30m.
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