Question

 A vertical stick 20m long casts a shadow 10m long on the ground. At the same time, a tower casts a shadow 50m long on the ground. The height of the tower is​

Answer 1

Answer:

In ΔABC & ΔADE

∠BCA=∠DEA=90

o

[Each are at 90

o

to the ground]

∠BAC=∠DAE [common angle]

∠CBA=∠EDA [∵ the sum will cast light a equal angles]

Hence, by AAA, ΔABC∼ΔADE

⇒

CA

BC

=

EA

DE⇒ 1020

= 50

DE

⇒DE=100

∴ The height of the tower is 100m.

solution

Answer 2

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