Question

a vertical Tower is 20 m height a man standing at some distance from the tower known that cosine of the angle of elevation of the top of the tower is 0.53 how far is he standing from the foot of the tower?

Answer 1

see the attachment ,
    A/c to quesion, 
cosine = 0.53
so, sine  =  $\sqrt{1-cosine^2}=\sqrt{1-0.53^2}=0.85$

now, tan = sine/cosine = 0.53/0.85 = 85/53
but tan = height of tower /distanceb/w tower and man
          85/53   = 20/D
            53D = 53*20 = 1060
            D = 12.47 m

hence, distance between man and tower = 12.47 m

Answer 2

Answer:

Step-by-step explanation:

Hope it will help you